Question 8%0d%0aA)Of the 72 students who have Ms. Darnell for Health/PE, 9 have an A. At this rate, how many of the 16 students in Ms. Jay’s homeroom would you expect to have an A?
To find the number of students in Ms. Jay's homeroom who would be expected to have an A, we can use proportions.
The proportion of students with an A in Ms. Darnell's class is 9/72. We can set up a proportion to find the expected number of students in Ms. Jay's homeroom (let's call it x) who would have an A:
9/72 = x/16
To solve for x, we can cross multiply:
72x = 9 * 16
72x = 144
Dividing both sides by 72:
x = 144/72
x = 2
Therefore, based on the given rate, we would expect 2 out of the 16 students in Ms. Jay's homeroom to have an A.