A rabbit is packing lunches for his children. He has 90 carrots and 72 leaves of lettuce. If he is giving each bunny the same number of carrots and the same number of leaves of lettuce, how many baby bunnies must he have? He will have no extra vegetables after he packs the lunches.(1 point)
Responses
18
18
6
6
9
9
3
The rabbit has a total of 90 carrots and 72 leaves of lettuce. To distribute them equally among the bunnies, we need to find the greatest common divisor (GCD) of 90 and 72.
The prime factorization of 90 is 2 * 3^2 * 5, and the prime factorization of 72 is 2^3 * 3^2.
To find the GCD, we take the smallest exponent for each prime factor that is common to both numbers. In this case, it is 2 * 3^2 = 18.
Therefore, the rabbit must have 18 baby bunnies.