which of the following is the correct ratio tan (7π/6)?
tan(7π/6) = -√3/2/-1/2 = √3
tan(7π/6) = -1/2/√3/2 = -√3/3
tan(7π/6) = -1/2/-√3/2 = √3/3
tan(7π/6) = 1/2/√3/2 = √3/3
tan(7π/6) = -√3/2/-1/2 = √3
tan(7π/6) = -1/2/√3/2 = -√3/3
tan(7π/6) = -1/2/-√3/2 = √3/3
tan(7π/6) = 1/2/√3/2 = √3/3