Suppose a spider was able to create one thread that would extend from the top right back corner of its tank to the bottom left front corner approximately how long would that thread need to be for the tank below the path of the spider's thread is shown with the red dotted line round your answer to the nearest tenth of an inch 35 in 16 in 12 in the diagonal of the bottom of the tank is how many inches to the nearest tenth of an inch the length of the spider's thread is how many inches
To find the length of the spider's thread, we can use the Pythagorean theorem. The diagonal of the bottom of the tank forms the hypotenuse of a right triangle with sides measuring 35 inches and 16 inches.
Using the Pythagorean theorem:
Diagonal^2 = Side1^2 + Side2^2
Diagonal^2 = 35^2 + 16^2
Diagonal^2 = 1225 + 256
Diagonal^2 = 1481
Diagonal ≈ √1481
Diagonal ≈ 38.5 inches
Therefore, the diagonal of the bottom of the tank measures approximately 38.5 inches to the nearest tenth of an inch.
To find the length of the spider's thread, we can use the same principle. The thread would be the hypotenuse of a right triangle with sides measuring 38.5 inches and 12 inches.
Using the Pythagorean theorem:
Thread^2 = Side1^2 + Side2^2
Thread^2 = 38.5^2 + 12^2
Thread^2 = 1482.25 + 144
Thread^2 = 1626.25
Thread ≈ √1626.25
Thread ≈ 40.3 inches
Therefore, the length of the spider's thread would be approximately 40.3 inches to the nearest tenth of an inch.