Use proportional relationships to solve this mixture problem. The incoming 6th-grade class has a choice between band or choir as an elective. There are four times as many seats in choir as there are in band. How many students can choose band if there is a total of 250 students?(1 point) Responses 50 students 50 students 250 students 250 students 124 students 124 students 200 students

Question

Use proportional relationships to solve this mixture problem. The incoming 6th-grade class has a choice between band or choir as an elective. There are four times as many seats in choir as there are in band. How many students can choose band if there is a total of 250 students?(1 point) Responses 50 students 50 students 250 students 250 students 124 students 124 students 200 students

Answer 1

Let's denote the number of students who can choose band as B and the number of students who can choose choir as C. According to the question, there are four times as many seats in choir as there are in band. Thus, we have the following proportional relationship:

C = 4B

Since there's a total of 250 students, the number of students who can choose band plus the number who can choose choir must equal 250:

B + C = 250

Now, using the proportional relationship C = 4B, we can substitute C in the equation above:

B + 4B = 250

Adding the B terms together gives us:

5B = 250

To find the number of students who can choose band (B), divide both sides of the equation by 5:

5B / 5 = 250 / 5
B = 50

So, there are 50 students who can choose band.