Which of the following is an ordered pair of the relation y = - 2/3 * x + 6' (1 point)
0 (0, - 2/3)
O (1, 4)
O (3, 8)
(3, 4)
To find an ordered pair that satisfies the relation \( y = -\frac{2}{3}x + 6 \), we have to plug the x-value from the ordered pair into the equation and see if the resulting y-value matches the one provided.
Let's do this for each pair:
Pair (0, -2/3):
Plugging x = 0 into the equation:
\( y = -\frac{2}{3}(0) + 6 = 0 + 6 = 6 \)
The correct y-value for x = 0 should be 6, not -2/3, so this pair does not satisfy the relation.
Pair (1, 4):
Plugging x = 1 into the equation:
\( y = -\frac{2}{3}(1) + 6 = -\frac{2}{3} + 6 = \frac{18}{3} - \frac{2}{3} = \frac{16}{3} \)
The correct y-value for x = 1 is \( \frac{16}{3} \) which is approximately 5.33, not 4, so this pair does not satisfy the relation.
Pair (3, 8):
Plugging x = 3 into the equation:
\( y = -\frac{2}{3}(3) + 6 = -2 + 6 = 4 \)
The correct y-value for x = 3 should be 4, not 8, so this pair does not satisfy the relation.
Pair (3, 4):
Plugging x = 3 into the equation:
\( y = -\frac{2}{3}(3) + 6 = -2 + 6 = 4 \)
The correct y-value for x = 3 is indeed 4, so this pair (3, 4) does satisfy the relation.
Therefore, the ordered pair that is part of the relation \( y = -\frac{2}{3}x + 6 \) is (3, 4).