Use the image to answer the question.
Four number lines are shown labeled from 1 to 4 vertically one below the other. The number lines range from negative 10 to 10 with numbers listed in unit increments.
The first number line has a closed point marked on 5. A leftward arrow is marked on the number line that originates at the closed point and goes beyond negative 10.
The second number line has an open point marked on 5. A leftward arrow is marked on the number line that originates at the open point and goes beyond negative 10.
The third number line has a closed point plotted on the number line between 4 and 5, just after the 4. A leftward arrow is marked on the number line that originates at the closed point and goes beyond negative 10.
The fourth number line has an open point plotted on the number line between 4 and 5, just after the 4. A leftward arrow is marked on the number line that originates at the open point and goes beyond negative 10.
Which graph shows the solution to 12x−4<56 ? Select 1, 2, 3, or 4 for your answer.
To solve the inequality 12x - 4 < 56, we need to find the solution where the left side of the inequality is less than the right side.
We can start by isolating the variable x.
12x < 56 + 4
12x < 60
Now, let's divide both sides of the inequality by 12 to isolate x.
x < 60/12
x < 5
So, the solution to the inequality is x is less than 5.
Now, let's analyze the given number lines to determine which one represents x < 5.
In the first number line, we have a closed point marked on 5. However, the inequality is strict (x < 5), so it should be an open point.
In the second number line, we have an open point marked on 5, which matches the strict inequality.
In the third and fourth number lines, we have points plotted between 4 and 5. However, the inequality is x < 5, so these points are not included in the solution.
Therefore, the graph that shows the solution to 12x - 4 < 56 is number line 2.
So, the answer is 2.