Which of the following is a point on the graph as described the function y= (2x+1) ^2-4
(-1,3)
(1,2)
(0,-2)
(-1,-5)
To find the points on the graph of the function y = (2x+1)^2 - 4, substitute the x-coordinate into the function to determine the y-coordinate.
(a) Substituting x = -1 into the function:
y = (2(-1)+1)^2 - 4
y = (-2+1)^2 - 4
y = (-1)^2 - 4
y = 1 - 4
y = -3
So, (-1, -3) is not a point on the graph of the function.
(b) Substituting x = 1 into the function:
y = (2(1)+1)^2 - 4
y = (2+1)^2 - 4
y = (3)^2 - 4
y = 9 - 4
y = 5
So, (1, 5) is not a point on the graph of the function.
(c) Substituting x = 0 into the function:
y = (2(0)+1)^2 - 4
y = (0+1)^2 - 4
y = (1)^2 - 4
y = 1 - 4
y = -3
So, (0, -3) is not a point on the graph of the function.
(d) Substituting x = -1 into the function:
y = (2(-1)+1)^2 - 4
y = (-2+1)^2 - 4
y = (-1)^2 - 4
y = 1 - 4
y = -3
So, (-1, -3) is not a point on the graph of the function.
None of the given points (-1,3), (1,2), (0,-2), (-1,-5) are on the graph of the function y = (2x+1)^2 - 4.