Simplify the expression.(−2i)(8i)
To multiply imaginary numbers, we can use the property that $i^2=-1$.
Thus, we have:
$$(-2i)(8i) = -16i^2$$
Now, substituting $i^2=-1$, we get:
$$-16i^2 = -16(-1) = 16$$
Therefore, $(-2i)(8i) = \boxed{16}.$