Use the Remainder Theorem to determine whether x + 1 is a divisor of
P(x)=2x3+4x2−2x+12
(1 point)
Responses
x+1 is a divisor of P(x)
x+1 is a divisor of P(x)
x+1 is not a divisor of P(x)
x+1 is not a divisor of P(x)
x+1 is a partial divisor of P(x)
x+1 is a partial divisor of P(x)
Not enough information has been provided.
To determine whether x + 1 is a divisor of P(x), we need to find the value of P(-1) and check if it equals zero according to the Remainder Theorem.
P(-1) = 2(-1)^3 + 4(-1)^2 - 2(-1) + 12
= -2 + 4 + 2 + 12
= 16
Since P(-1) is not equal to zero, x + 1 is not a divisor of P(x).
Therefore, the correct response is:
x+1 is not a divisor of P(x)