The solution (2, 1)
is feasible for which of the following inequalities?(1 point)
Responses
−2x−4y>−6
negative 2 x minus 4 y is greater than negative 6
−2x+4y≥0
negative 2 x plus 4 y is greater than or equal to 0
2x−4y<0
2x−4y<0
2x+4y≤6
sorry -- if x=2 and y=1, then 2x+4y = 8, which is not less than 6
so, B
The solution (2, 1) is feasible for the inequality −2x+4y≥0.
To determine which of the inequalities the solution (2, 1) is feasible for, you need to substitute the values of x and y in each inequality and check if the inequality is true.
Let's start with the first inequality: −2x−4y>−6
Substituting x = 2 and y = 1, we have:
−2(2)−4(1) > −6
-4 - 4 > -6
-8 > -6
Since -8 is greater than -6, the first inequality is true.
Now let's move on to the second inequality: −2x+4y≥0
Substituting x = 2 and y = 1, we have:
−2(2)+4(1) ≥ 0
-4 + 4 ≥ 0
0 ≥ 0
Since 0 is greater than or equal to 0, the second inequality is true.
Next is the third inequality: 2x−4y<0
Substituting x = 2 and y = 1, we have:
2(2)−4(1) < 0
4 - 4 < 0
0 < 0
Since 0 is not less than 0, the third inequality is false.
Finally, let's check the fourth inequality: 2x+4y≤6
Substituting x = 2 and y = 1, we have:
2(2)+4(1) ≤ 6
4 + 4 ≤ 6
8 ≤ 6
Since 8 is not less than or equal to 6, the fourth inequality is false.
Based on these calculations, the solution (2, 1) is feasible for the first two inequalities, −2x−4y>−6 and −2x+4y≥0.