Use the equation for motion to answer the question.
x=x0+v0t+12at2
An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?
(1 point)
Responses
60 m
60 m
30 m
30 m
17 m
17 m
32 m
To find the final position of the object after 1 second, we need to substitute the given values into the equation for motion.
Given:
x0 = 2 m (starting position)
v0 = 15 m/s (starting velocity)
t = 1 s (time)
Plugging these values into the equation:
x = x0 + v0t + (1/2)at^2
x = 2 + 15(1) + (1/2)(a)(1)^2
Since the object is moving at a constant speed, its acceleration is 0 m/s^2. Therefore, we can further simplify the equation to:
x = 2 + 15(1) + (1/2)(0)(1)^2
x = 2 + 15 + 0
x = 17
Therefore, the final position of the object after 1 second is 17 m.
The correct option is: 17 m.