Calculate the number of atoms of carbon present in 25 gram of caco3?
To calculate the number of atoms of carbon present in 25 grams of CaCO3, we need to consider the molar mass of CaCO3 and the molar mass of carbon.
The molar mass of CaCO3 is calculated as follows:
One atom of calcium (Ca) has a molar mass of 40.08 g/mol.
One atom of carbon (C) has a molar mass of 12.01 g/mol.
Three atoms of oxygen (O) have a combined molar mass of 3 * 16.00 g/mol = 48.00 g/mol.
Therefore, the molar mass of CaCO3 is 40.08 g/mol + 12.01 g/mol + 48.00 g/mol = 100.09 g/mol.
Now we can calculate the number of moles of CaCO3 in 25 grams:
Number of moles = Mass / Molar mass
Number of moles = 25 g / 100.09 g/mol = 0.2495 mol
Since each mole of CaCO3 contains one mole of carbon atoms, the number of carbon atoms can be calculated using Avogadro's number (6.022 × 10^23 atoms/mol):
Number of carbon atoms = Number of moles * Avogadro's number
Number of carbon atoms = 0.2495 mol * 6.022 × 10^23 atoms/mol = 1.499 × 10^23 atoms
Therefore, there are approximately 1.499 × 10^23 atoms of carbon present in 25 grams of CaCO3.