person a wants to walk to person b's house that is 3 miles away. person a's walking speed is 3 mph while person b's biking speed is 12m, 4 minutes later person a's mom notices person a forgot something and sends person a's brother to get it, how fast should person a's brother travel to catch up to person a?
ADD ANSWER
+5 PTS
ASK AI
To calculate the speed at which person A's brother should travel to catch up to person A, we need to consider the time it takes for person A to reach person B's house and the time person A's brother has to catch up.
Person A's walking speed is 3 mph, so it would take person A 1 hour to walk the 3 miles to person B's house.
However, we know that person A forgot something and person A's brother is sent to catch up with person A. We are told that person A's brother starts 4 minutes later. To compare the times of person A and person A's brother, we need to convert the 4 minutes into hours. There are 60 minutes in an hour, so 4 minutes is equal to 4/60 = 0.067 hours.
Now, let's calculate the time it takes for person A's brother to catch up with person A. Person A's brother needs to cover the same 3-mile distance, but within a shorter time frame than person A. Since person A's brother starts 4 minutes later, we can subtract this time from the time it takes for person A to cover the 3 miles.
Time taken for person A to cover the 3 miles = Distance / Speed = 3 miles / 3 mph = 1 hour
Time taken for person A's brother to cover the 3 miles = Time taken for person A - 4 minutes
= 1 hour - 0.067 hours = 0.933 hours
Now we can calculate the speed at which person A's brother should travel to catch up to person A. The speed is equal to the distance divided by the time.
Speed = Distance / Time = 3 miles / 0.933 hours
≈ 3.214 mph
Therefore, person A's brother should travel at a speed of approximately 3.214 mph to catch up with person A.