A store owner needs to keep track of their inventory (the number of each item they have). When items are purchased, the inventory needs to decrease. When items are restocked, the inventory needs to increase. Outline an algorithm that can be used by this owner, describing necessary data structures and computational thinking concepts.

Explain the concept of Big-O notation and describe the efficiency of the algorithms you just designed when the inventory needs to be updated or printed.

Algorithm for Inventory Management:

1. Initialize an empty data structure called inventory. This could be a dictionary/hash map with item names as keys and the corresponding quantity as values.

2. To decrease inventory:
a. Take input for the item name and the quantity to be purchased.
b. Check if the item exists in the inventory. If it does, subtract the purchased quantity from the current quantity.
c. If the quantity becomes zero or less, remove the item from the inventory (optional).

3. To increase inventory:
a. Take input for the item name and the quantity to be restocked.
b. Check if the item exists in the inventory. If it does, add the restocked quantity to the current quantity.
c. If the item does not exist, add it to the inventory with the restocked quantity.

4. To print inventory:
a. Iterate over the inventory data structure and print each item name with its corresponding quantity.

Big-O Notation:

Big-O notation is a way to analyze and describe the efficiency (time and space) of algorithms by expressing their worst-case runtime complexity. It provides an upper bound estimate of how the algorithm's performance scales with the input size.

In the inventory management algorithm outlined above:
- Decreasing inventory requires checking if an item exists, which can be done in O(1) time complexity using a dictionary/hash map. Subtracting or removing the item also takes O(1) time in average cases.
- Increasing inventory involves checking if an item exists (O(1) time), adding or updating the item in the dictionary (O(1) time), and potentially resizing the dictionary if needed (amortized O(1) time complexity).
- Printing the inventory requires iterating over all items in the dictionary, resulting in O(n) time complexity, where n is the number of items in the inventory.

Overall, the efficiency of these algorithms is quite good. Updating the inventory (decreasing or increasing) is constant time or nearly constant time operations. The only operation that scales with the inventory size is printing, which takes linear time complexity.