Camila needs to fix the window on the front of her house. The bottom of the window is 16 ft. from the ground. She only has a 20 ft. ladder. How far from the base of the house should she set up the ladder so that the top of the ladder is exactly at the bottom of the window? not 4ft
To determine the distance from the base of the house where Camila should set up the ladder, we need to find the distance from the top of the ladder to the bottom of the window.
Since the bottom of the window is 16 ft. from the ground, and Camila has a 20 ft. ladder, the top of the ladder should be 16 ft. + 20 ft. = <<16+20=36>>36 ft. from the ground.
Therefore, Camila should set up the ladder 36 ft. from the base of the house.
wrong
I apologize for the incorrect response.
To determine the distance from the base of the house where Camila should set up the ladder, we need to subtract the height of the ladder (20 ft.) from the height of the window sill (16 ft.).
16 ft. - 20 ft. = -4 ft.
Since it's not possible to set up the ladder at a negative distance from the base of the house, Camila cannot use the 20 ft. ladder to fix the window. She would require a taller ladder or find an alternative solution.
try again
Apologies for the confusion. Let's try again.
To determine the distance from the base of the house where Camila should set up the ladder, we need to subtract the height of the window from the length of the ladder.
If the bottom of the window is 16 ft. from the ground and the ladder is 20 ft. long, we need to subtract 16 ft. from 20 ft. to find the distance from the base of the house where Camila should set up the ladder.
20 ft. - 16 ft. = 4 ft.
Therefore, Camila should set up the ladder 4 ft. from the base of the house so that the top of the ladder is exactly at the bottom of the window.
nope try agian Camila needs to fix the window on the front of her house. The bottom of the window is 16 ft. from the ground. She only has a 20 ft. ladder. How far from the base of the house should she set up the ladder so that the top of the ladder is exactly at the bottom of the window?
Apologies for the previous incorrect response. Let's try again.
To determine how far from the base of the house Camila should set up the ladder, we need to find the vertical distance from the ground to the bottom of the window and subtract that from the height of the ladder.
Given that the bottom of the window is 16 ft. from the ground and Camila has a 20 ft. ladder, we need to subtract 16 ft. from 20 ft. to find the distance.
20 ft. - 16 ft. = 4 ft.
Therefore, Camila should set up the ladder 4 ft. from the base of the house so that the top of the ladder is exactly at the bottom of the window.
use the pythagorean theorem
Apologies once again. Let's use the Pythagorean theorem to find the correct distance.
In this case, the distance from the base of the house where Camila should set up the ladder can be found using the Pythagorean theorem, which states that for a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this scenario, the ladder acts as the hypotenuse, the distance from the base of the house to the ladder's placement acts as one side, and the height from the ground to the bottom of the window acts as the other side.
Let's denote the distance from the base of the house to the ladder's placement as x.
Applying the Pythagorean theorem, we have:
x^2 + 16^2 = 20^2
Simplifying this equation:
x^2 + 256 = 400
Subtracting 256 from both sides:
x^2 = 400 - 256
x^2 = 144
Taking the square root of both sides gives us:
x = √144
x = 12
Therefore, Camila should set up the ladder 12 ft. from the base of the house so that the top of the ladder is exactly at the bottom of the window.
Use the image to answer the question.
A rectangle is formed from two right triangles. The base of the rectangle measures 80 yards and is labeled Johnson Avenue. The top of the rectangle is labeled Edison Avenue. The left side joining both the avenues is labeled 41st street and measures 60 yards. The right side of the rectangle is labeled 42nd street. A bank is located at the vertex of 41st street and Edison Avenue. The hypotenuse joining the bank and the vertex of Johnson Avenue and 42nd street is labeled park.
Sylvia likes to walk to work when the weather is nice. She works at the bank at the corner of 41st Street and Edison Avenue. Her house is at the corner of 42nd Street and Johnson Avenue. She can walk down Johnson Avenue and turn right on 41st Street, or she can walk through the park. The distance from 42nd Street to 41st Street is 80 yards, and it is 60 yards from Johnson Avenue to Edison Avenue. Assuming the street intersections are 90° angles, how much shorter is it for Sylvia to walk through the park?
(1 point)
If Sylvia walks through the park instead of straight down Johnson Avenue and straight down 41st Street, the walk will be
yards shorter.use the pythagorean theorem