A line passes through (–3, –1) and is parallel to the graph of y = 2x + 3. What equation represents the line in slope-intercept form?
y = 2x + 2
y = 2x + 5
y = 2x – 5
y = 2x – 2
Since the line is parallel to the graph of y = 2x + 3, it has the same slope of 2. We can use the point-slope form of a linear equation to find the equation of the line:
y - y1 = m(x - x1)
Substituting in the values of the point (-3, -1) and the slope 2, we get:
y - (-1) = 2(x - (-3))
Simplifying,
y + 1 = 2(x + 3)
Expanding,
y + 1 = 2x + 6
Subtracting 1 from both sides,
y = 2x + 5
Therefore, the equation of the line in slope-intercept form is y = 2x + 5. Answer: \boxed{y=2x+5}.