Write an equation of the line that passes through the given points
(-4, -2) and (-3, 5)
First, let's find the slope of the line using the formula: m = (y2-y1)/(x2-x1).
Using the points (-4,-2) and (-3,5), we have:
m = (5-(-2))/(-3-(-4))
m = (5+2)/(-3+4)
m = (7)/1
m = 7
So the slope of the line is 7.
Now, let's use the point-slope form of a linear equation, y - y1 = m(x - x1), where (x1, y1) are the coordinates of any point on the line.
Using the point (-3,5), we have:
y - 5 = 7(x - (-3))
Expanding:
y - 5 = 7(x + 3)
y - 5 = 7x + 21
Now, rearranging the equation to find the slope-intercept form y = mx + b:
y = 7x + 21 + 5
y = 7x + 26
Therefore, the equation of the line that passes through the given points (-4, -2) and (-3, 5) is y = 7x + 26.