(1 point)
Responses
1,280+30h=01 comma 280 plus 30 h is equal to 0
10−30h=010 minus 30 h is equal to 0
1,280−30h=01 comma 280 minus 30 h is equal to 0
These equations cannot be solved to find a numerical value for h because they are inconsistent. In each equation, the left side is a constant and the right side is equal to 0. This means that no matter what value of h we choose, the equation will never be satisfied.
Yes, the statement is true. The equations are inconsistent and cannot be solved to find a numerical value for h.
To solve these equations, you need to isolate the variable "h" on one side of the equation. Let's solve each equation step by step:
1. 1,280 + 30h = 0
Start by subtracting 1,280 from both sides:
1,280 + 30h - 1,280 = 0 - 1,280
Simplify:
30h = -1,280
Divide both sides of the equation by 30 to solve for "h":
h = -1,280 / 30
Simplify the division:
h = -42.67
So, for the first equation, h equals approximately -42.67.
2. 10 - 30h = 0
Start by subtracting 10 from both sides:
10 - 30h - 10 = 0 - 10
Simplify:
-30h = -10
Divide both sides of the equation by -30 to solve for "h":
h = -10 / -30
Simplify the division:
h = 0.33
So, for the second equation, h equals approximately 0.33.
3. 1,280 - 30h = 0
Start by subtracting 1,280 from both sides:
1,280 - 30h - 1,280 = 0 - 1,280
Simplify:
-30h = -1,280
Divide both sides of the equation by -30 to solve for "h":
h = -1,280 / -30
Simplify the division:
h = 42.67
So, for the third equation, h equals approximately 42.67.