Scientist that heats 30 grams of calcium carbonate CaCO3 in the chemical reaction shown what is the total mass of the products
The chemical equation for the reaction of heating calcium carbonate (CaCO3) is:
CaCO3(s) -> CaO(s) + CO2(g)
According to the equation, 1 mole of CaCO3 produces 1 mole of CaO and 1 mole of CO2.
To determine the total mass of the products, we first need to calculate the moles of CaCO3.
Given mass of CaCO3 = 30 grams
Molar mass of CaCO3 = 40.08 + 12.01 + (16.00 * 3) = 100.09 g/mol
Moles of CaCO3 = Mass / Molar mass = 30 g / 100.09 g/mol = 0.2996 mol (approximately)
Since one mole of CaCO3 produces one mole of CaO and one mole of CO2, the moles of CaO and CO2 produced will also be 0.2996 mol each.
To find the mass of each product, we need to multiply their respective moles by their molar masses.
Molar mass of CaO = 40.08 g/mol
Molar mass of CO2 = 12.01 + (16.00 * 2) = 44.01 g/mol
Mass of CaO = Moles of CaO * Molar mass of CaO = 0.2996 mol * 40.08 g/mol = 11.99 grams (approximately)
Mass of CO2 = Moles of CO2 * Molar mass of CO2 = 0.2996 mol * 44.01 g/mol = 13.18 grams (approximately)
Therefore, the total mass of the products (CaO + CO2) is approximately 11.99 grams + 13.18 grams = 25.17 grams.