A gas at 300 K and under 1 bar of pressure takes up 1.2 L of volume.
The gas is quickly compressed to 9 bars and the new temperature is measured to be 1200 K. Use the combined gas law to calculate the new volume of the gas. Show your work!
This is how I set up my problem, Please solve it like it’s shown here please.
P1 V1/T1 = P2 V2/ T2
(1 Bar)(1.2L) / 300k = (9 Bar) * V/ 1200 k
To solve for the new volume (V2), we can rearrange the combined gas law equation as follows:
P1V1/T1 = P2V2/T2
Plugging in the given values:
(1 bar)(1.2 L) / 300 K = (9 bar) * V2 / 1200 K
Now we can solve for V2:
(1 bar)(1.2 L)(1200 K) = (9 bar)(V2)(300 K)
(1.2)(1200) = (9)(V2)
1440 = 9V2
Divide both sides by 9:
V2 = 1440 / 9
V2 = 160 L
So the new volume of the gas is 160 L.