an office manager booked 67 airline tickets . he booked 8 more tickets on airlines A than airlines B . On airlines C he booked 4 more than thrice as many tickets as on Airlime B. How many tickets did he book on each airline?
Let's assume the number of tickets booked on airline B is x.
Then, the number of tickets booked on airline A is x + 8.
And the number of tickets booked on airline C is 3x + 4.
Total number of tickets booked = x + (x + 8) + (3x + 4) = 67.
Simplifying the equation, we get 5x + 12 = 67.
Subtracting 12 from both sides, we get 5x = 55.
Dividing both sides by 5, we get x = 11.
So, the number of tickets booked on airline B = x = 11.
The number of tickets booked on airline A = x + 8 = 11 + 8 = 19.
And the number of tickets booked on airline C = 3x + 4 = 3(11) + 4 = 33 + 4 = 37. Answer: \boxed{11, 19, 37}.