use the chemical equation to awnser the question
Br2(l) + 2Nal(aq) --> I2(s) + 2NaBr(aq)
Which elements are oxidized and reduced in the reaction
In the given chemical equation:
Br2(l) + 2NaI(aq) --> I2(s) + 2NaBr(aq)
Bromine (Br) is being reduced from a zero oxidation state in Br2(l) to a -1 oxidation state in NaBr(aq). Therefore, bromine is being reduced.
Iodine (I) is being oxidized from a -1 oxidation state in NaI(aq) to a 0 oxidation state in I2(s). Therefore, iodine is being oxidized.