To raise money, the student council at a local middle school is hosting a talent show. Tickets are sold for $5.00 for students (x) and $8.00 for adults (y). The goal is to raise a total of $1,575.00. Which of the following is a viable solution for the number of student and adult tickets that can be sold?
A. (125, 115)
B. (81, 146.25)
C. (115, 125)
D. (371, -35)
The problem can be represented by the equations 5x + 8y = 1575.
We can check each option to see if they satisfy the equation.
A. (125, 115)
Using these values in the equation: 5(125) + 8(115) = 625 + 920 = 1545
This does not equal to 1575, so option A is not a viable solution.
B. (81, 146.25)
Using these values in the equation: 5(81) + 8(146.25) = 405 + 1170 = 1575
This equals to 1575, so option B is a viable solution.
C. (115, 125)
Using these values in the equation: 5(115) + 8(125) = 575 + 1000 = 1575
This equals to 1575, so option C is a viable solution.
D. (371, -35)
Using these values in the equation: 5(371) + 8(-35) = 1855 - 280 = 1575
This equals to 1575, so option D is a viable solution.
Therefore, the viable solutions for the number of student and adult tickets that can be sold are B. (81, 146.25), C. (115, 125), and D. (371, -35).