To raise money, the student council at a local middle school is hosting a talent show. Tickets are sold for $5.00 for students (x) and $8.00 for adults (y). The goal is to raise a total of $1,575.00. Which of the following is a viable solution for the number of student and adult tickets that can be sold?
Let's assume that the number of student tickets sold is x and the number of adult tickets sold is y.
The total amount raised from student tickets is 5x.
The total amount raised from adult tickets is 8y.
According to the information given:
5x + 8y = 1,575
To find a viable solution, we need to determine pairs of integers (x, y) that satisfy this equation.
Let's try some values for x and y:
- If x = 1 and y = 195, then 5x + 8y = 5(1) + 8(195) = 1,580, which is not equal to 1,575.
- If x = 2 and y = 195, then 5x + 8y = 5(2) + 8(195) = 1,589, which is also not equal to 1,575.
- If x = 3 and y = 193, then 5x + 8y = 5(3) + 8(193) = 1,567, which is not equal to 1,575.
- If x = 3 and y = 194, then 5x + 8y = 5(3) + 8(194) = 1,575, which is equal to the desired amount.
Therefore, a viable solution is x = 3 student tickets and y = 194 adult tickets.