Use the chemical reaction to answer the question.
CaCO3→CO2+CaO
A scientist heats 30 grams of calcium carbonate (CaCO3
) in the chemical reaction shown. What is the total mass of the products?
(1 point)
Responses
10 grams
10 grams
60 grams
60 grams
15 grams
15 grams
30 grams
30 grams
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To find the total mass of the products, we need to determine the molar masses of CO2 and CaO. The molar mass of CO2 is 44.01 g/mol (12.01 g/mol for carbon + 2(16.00 g/mol) for oxygen) and the molar mass of CaO is 56.08 g/mol (40.08 g/mol for calcium + 16.00 g/mol for oxygen).
Since the chemical reaction is 1 mole of CaCO3 producing 1 mole of CO2 and 1 mole of CaO, we can find the amount of moles present in 30 grams of CaCO3.
The molar mass of CaCO3 is 100.09 g/mol (40.08 g/mol for calcium + 12.01 g/mol for carbon + 3(16.00 g/mol) for oxygen). Therefore, 30 grams of CaCO3 is equal to 0.2997 moles (30 g / 100.09 g/mol).
Since the molar ratio of CaCO3 to CO2 is 1:1 and the molar ratio of CaCO3 to CaO is also 1:1, the amount of moles of CO2 and CaO produced will also be 0.2997 moles.
To find the mass of CO2 and CaO, we multiply the amount of moles by the molar mass.
Mass of CO2 = 0.2997 moles x 44.01 g/mol = 13.19 grams
Mass of CaO = 0.2997 moles x 56.08 g/mol = 16.80 grams
Therefore, the total mass of the products is 13.19 grams + 16.80 grams = 29.99 grams. Rounding to the nearest whole number, the total mass of the products is 30 grams.
So the correct answer is 30 grams.