A particular hybrid car travels approximately 294 mi on 6 gal of gas. Find the amount of gas required for a 735-mi trip.
To find the amount of gas required for a 735-mi trip, we can set up a proportion with the given information:
294 mi / 6 gal = 735 mi / x gal
Cross-multiplying, we get:
294 mi * x gal = 6 gal * 735 mi
Dividing both sides of the equation by 294 mi, we have:
x gal = (6 gal * 735 mi) / 294 mi
Simplifying, we find:
x gal ≈ 15 gal
Therefore, the amount of gas required for a 735-mi trip is approximately 15 gallons.