Use proportional relationships to solve this mixture problem. The incoming 6th-grade class has a choice between band or choir as an elective. There are four times as many seats in choir as there are in band. How many students can choose band if there is a total of 250 students? (1 point)
Let's represent the number of seats in band as "b" and the number of seats in choir as "c".
According to the problem, there are four times as many seats in choir as there are in band.
So, we can write the equation c = 4b.
Also, we know that the total number of students is 250.
Since the students have the choice between band and choir, the number of students in band (b) and the number of students in choir (c) will add up to 250.
Therefore, we can write the equation b + c = 250.
Now, substitute the value of c from the first equation into the second equation: b + 4b = 250.
Combine like terms: 5b = 250.
Divide both sides by 5: b = 50.
Therefore, there are 50 seats in band, which means that 50 students can choose band. Answer: \boxed{50}.