Line CD passes through points C(1,3) and D (4,-3) if the equation of the line is written in slope intercept form what is the value of b
To find the equation of the line in slope-intercept form (y = mx + b), we need to find the slope (m) and the y-intercept (b).
Given the two points C(1,3) and D(4,-3), we can find the slope using the formula:
m = (y2 - y1) / (x2 - x1)
Substituting the coordinates of the points C and D:
m = (-3 - 3) / (4 - 1)
m = -6 / 3
m = -2
Now that we have the slope (m = -2), we can substitute it into the slope-intercept form equation to find the value of b. Since we're given that the line passes through points C(1,3), we can substitute x = 1 and y = 3:
3 = -2(1) + b
Multiplying -2 by 1 and rearranging the equation, we get:
3 = -2 + b
b = 3 + 2
b = 5
Therefore, the value of b is 5.