Use proportional relationships to solve this mixture problem. The incoming 6th-grade class has a choice between band or choir as an elective. There are four times as many seats in choir as there are in band. How many students can choose band if there is a total of 250 students?(1 point)
Responses
124 students
124 students
250 students
250 students
200 students
200 students
50 students
The number of seats in choir is four times the number of seats in band. Therefore, we can set up a proportion:
Band seats / Choir seats = Band students / Choir students
Let's assume the number of seats in band is x. Then the number of seats in choir is 4x.
x / 4x = Band students / 250
Cross-multiplying, we get:
4x * Band students = x * 250
Simplifying, we have:
4 * Band students = 250
Dividing both sides by 4:
Band students = 250 / 4
Band students = 62.5
Since we can't have a fraction of students, the closest whole number is 63 students. Therefore, 63 students can choose band.
Use proportional relationships to solve this mixture problem. The incoming 6th-grade class has a choice between band or choir as an elective. There are four times as many seats in choir as there are in band. How many students can choose band if there is a total of 250 students?(1 point)
Responses
124 students
124 students
250 students
250 students
200 students
200 students
50 students
choose one
Let's set up a proportion using the information given:
Band seats / Choir seats = Band students / Choir students
Since there are four times as many seats in choir as there are in band, we can let the number of seats in band be x, and the number of seats in choir be 4x.
x / 4x = Band students / 250
Cross-multiplying, we get:
4x * Band students = x * 250
Simplifying, we have:
4 * Band students = 250
Dividing both sides by 4:
Band students = 250 / 4
Band students = 62.5
Since we can't have a fraction of students, the closest whole number is 63 students. Therefore, 63 students can choose band.
you cant have 63
Apologies for the confusion. You are correct, we cannot have a fraction of students.
Since we know that the number of choir seats is four times the number of band seats, we can set up the proportion:
Band seats / Choir seats = Band students / Choir students
Let's assume the number of band seats is x. Then the number of choir seats would be 4x.
x / 4x = Band students / 250
Cross-multiplying, we get:
4x * Band students = x * 250
Simplifying, we have:
4 * Band students = 250
Dividing both sides by 4:
Band students = 250 / 4
Band students = 62.5
Since we can't have a fraction of students, the closest whole number is 62. Therefore, 62 students can choose band.
nope
Apologies once again for the error. Let's approach the problem again using proportional relationships.
Let's assume that the number of band seats is x. Since there are four times as many seats in choir as in band, we can say the number of choir seats is 4x.
Now, let's set up the proportion:
Band seats / Choir seats = Band students / Total students
x / 4x = Band students / 250
To solve for Band students, let's cross-multiply:
x * 250 = 4x
250x = 4x
Subtract 4x from both sides:
250x - 4x = 0
246x = 0
Divide both sides by 246:
x = 0
Since we can't have zero band seats, there must be an error in the initial statement. Could you please double-check the information?
Use proportional relationships to solve this mixture problem. The incoming 6th-grade class has a choice between band or choir as an elective. There are four times as many seats in choir as there are in band. How many students can choose band if there is a total of 250 students?(1 point)
Responses
124 students
124 students
250 students
250 students
200 students
200 students
50 students
CHOOSE ONE
Apologies for the confusion earlier. Let's approach the problem one more time using proportional relationships.
Let the number of band seats be x. Since there are four times as many seats in choir as in band, the number of choir seats would be 4x.
Now, let's set up the proportion:
Band seats / Choir seats = Band students / Choir students
x / 4x = Band students / 250
Cross-multiplying, we get:
x * 250 = 4x
250x = 4x
Subtract 4x from both sides:
250x - 4x = 0
246x = 0
Divide both sides by 246:
x = 0
Since we can't have zero band seats, it appears there is an error in the problem statement. The correct answer cannot be determined without the accurate information.
To solve this mixture problem using proportional relationships, we need to establish the ratio between the number of seats in the band and the number of seats in the choir.
Given that there are four times as many seats in the choir as in the band, we can set up the following ratio:
Band seats : Choir seats = 1 : 4
Now, let's find the number of seats in the band. We know that the total number of students is 250, and we'll assume that all the students choose either band or choir.
Let's represent the number of seats in the band as "x". Then, we can represent the number of seats in the choir as "4x" since there are four times as many seats in the choir.
Now, we can set up an equation to find the value of x:
x + 4x = 250
Combining like terms, we get:
5x = 250
Dividing both sides by 5, we find:
x = 50
So, the number of students that can choose band is 50.
Therefore, the correct choice is:
50 students