An archer shot a 0.06 kg arrow at a target. The arrow accelerated at 5,000 m/s/s to reach a speed of 50.0 m/s as it left the bow. During this ACCELERATION, what was the net force on the arrow to the nearest newton?
and how much is the acceleration, speed, mass, or force?
To find the net force on the arrow during the acceleration, we can use Newton's second law of motion, which states that the net force (F_net) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a):
F_net = m * a
Given:
Mass of the arrow (m) = 0.06 kg
Acceleration of the arrow (a) = 5,000 m/s^2
Plugging in the values into the formula, we get:
F_net = 0.06 kg * 5,000 m/s^2
= 300 N
Therefore, the net force on the arrow during the acceleration is 300 Newtons (N) to the nearest newton.
To summarize:
- Acceleration: 5,000 m/s^2
- Speed: 50.0 m/s
- Mass: 0.06 kg
- Net force: 300 N