for what value of a will 8x10^3 be 40 times larger than ax10^2?
To find the value of "a" that makes 8x10^3 40 times larger than ax10^2, we can set up the following equation:
8x10^3 = 40(ax10^2)
Simplifying the equation:
8x10^3 = 40ax10^2
Dividing both sides by 40 x 10^2:
(8x10^3) / (40x10^2) = a
Simplifying the equation further:
(8/40) x (10^3/10^2) = a
(1/5) x 10^1 = a
Multiplying 1/5 by 10^1:
(1/5) x 10 = a
a = 2
Therefore, the value of "a" that makes 8x10^3 40 times larger than ax10^2 is 2.