Dominic, Josephine and George shared a sum of money. The ratio of the amount of money Dominic received to the amount of money Josephine received to the amount of money George received was 3:5:9. Dominic received $60. How much was the sum of money?
The ratio of the amount of money Dominic received to the amount of money Josephine received to the amount of money George received was 3:5:9.
So, for every 3 parts of the ratio, Dominic received $60/3 = $<<60/3=20>>20.
Since Dominic received $60, then the total ratio is composed of 3 + 5 + 9 = <<3+5+9=17>>17 parts.
Therefore, the sum of money is $20 x 17 = $<<20*17=340>>340. Answer: \boxed{340}.