Admission to a baseball game is 4.50$ for general admission and 6.50$ for reserved seats the receipts were 4757.50 for 895 paid admissions how many of each ticket were sold
Let's assume that the number of general admissions sold is x and the number of reserved seats sold is y.
The total number of admissions sold is x + y = 895. (Equation 1)
The total revenue from general admission is 4.50x. (Equation 2)
The total revenue from reserved seats is 6.50y. (Equation 3)
The total revenue from admissions is the sum of the revenue from general admission and reserved seats, which is $4757.50. Therefore, we can write the equation as:
4.50x + 6.50y = 4757.50. (Equation 4)
We can solve this system of equations to find the values of x and y.
From equation 1, we can rearrange it to get x = 895 - y. (Equation 5)
Substituting Equation 5 into Equation 4:
4.50(895 - y) + 6.50y = 4757.50.
Expanding the equation:
4027.50 - 4.50y + 6.50y = 4757.50.
Combining like terms:
2.00y = 730.
Dividing both sides of the equation by 2.00:
y = 365.
Substituting this value of y into Equation 1:
x + 365 = 895.
Subtracting 365 from both sides of the equation:
x = 530.
Therefore, there were 530 general admissions sold and 365 reserved seats sold.