Write the equations of the tangent lines when x = 1
To find the equations of the tangent lines when x = 1, we need the derivative of the function at that point. Let's call the function f(x).
First, we need to find f'(x), which represents the derivative of the function. Once we have f'(x), we can substitute x = 1 to find the slope of the tangent line at that point.
Let's assume the function f(x) = y.
Step 1: Find f'(x)
f'(x) = dy/dx
Step 2: Substitute x = 1 into f'(x)
f'(1) = dy/dx at x = 1
Once we have f'(1), we can find the slope of the tangent line(s) at x = 1.
Step 3: Find the equations of the tangent line(s)
The equation of a line is y = mx + b, where m is the slope and b is the y-intercept.
Since we have the slope, we can write the equation of the tangent line(s):
y = f'(1)(x - 1) + f(1).
Please provide the function f(x) or more information about the problem to calculate f'(1) and f(1) and find the specific tangent line(s).