transform the liner equation -2y=14-6 to slop-intercept form
To transform the linear equation -2y = 14 - 6 into slope-intercept form, we need to isolate y on one side of the equation.
First, let's simplify the right side of the equation:
-2y = 14 - 6
-2y = 8
Next, divide both sides of the equation by -2 to solve for y:
(-2y) / -2 = 8 / -2
y = -4
Thus, the equation -2y = 14 - 6 can be written in slope-intercept form as y = -4.
opps i meant transform the liner equation -2y=14-6x to slop-intercept form
To transform the linear equation -2y = 14 - 6x into slope-intercept form (y = mx + b), we need to isolate y on one side of the equation.
First, let's simplify the right side of the equation:
-2y = 14 - 6x
Next, divide both sides of the equation by -2 to solve for y:
(-2y) / -2 = (14 - 6x) / -2
y = -7 + 3x
Thus, the equation -2y = 14 - 6x can be written in slope-intercept form as y = 3x - 7.
To transform the linear equation `-2y = 14-6` to slope-intercept form (`y = mx + b`), where `m` represents the slope and `b` represents the y-intercept, we need to isolate the variable `y`.
Let's solve step by step:
1. Start with the given equation:
`-2y = 14 - 6`
2. Simplify the right side of the equation:
`-2y = 8`
3. Divide both sides of the equation by `-2` to isolate `y`:
`-2y/-2 = 8/-2`
`y = -4`
Therefore, the equation `-2y = 14-6` can be rewritten in slope-intercept form as `y = -4`.
In this case, the equation is a horizontal line with a y-intercept of -4 and no slope, as the value of `x` does not affect the value of `y`.