JL¯¯¯¯¯¯¯is a perpendicular bisector of KM¯¯¯¯¯¯¯¯¯¯. Hallie locates point H along line segment JL¯¯¯¯¯¯¯. If the length of KH¯¯¯¯¯¯¯¯¯ is given by 6y+3 and the length of HM¯¯¯¯¯¯¯¯¯¯ is given by 2y+7, what is the length in units of segment HM¯¯¯¯¯¯¯¯¯¯? (1 point)
Since JL is the perpendicular bisector of KM, this means that KH is equal to HM. Therefore, 6y+3 = 2y+7. Subtracting 2y from both sides gives 4y+3 = 7. Subtracting 3 from both sides gives 4y = 4, so y = 1. Therefore, the length of HM is 2y+7 = 2(1)+7 = 2+7 = <<2*1+7=9>>9 units. Answer: \boxed{9}.
