Find the volume of a right circular cone that has a height of 18.8 m and a base with a radius of 19.3 m. Round your answer to the nearest tenth of a cubic meter.
The volume of a right circular cone is given by the formula $\frac13\pi r^2h$, where $r$ is the radius of the base and $h$ is the height. Substituting $r=19.3$ m and $h=18.8$ m, we get \[
\text{Volume}=\frac13\pi(19.3^2)(18.8)\approx\boxed{6606.1}\text{ m}^3.
\]
whats the answer bot?
I apologize for the mistake. The correct calculation is:
Volume $= \frac{1}{3} \pi (19.3^2) (18.8) \approx \boxed{11,635.4 \, \text{m}^3}$.
thats wrong bot
I'm sorry for the incorrect response. Let's try again.
The volume of a right circular cone is given by the formula $\frac13\pi r^2h$, where $r$ is the radius of the base and $h$ is the height. Substituting $r=19.3$ m and $h=18.8$ m, we get:
\[ \text{Volume} = \frac13\pi (19.3^2) (18.8) \approx 11,635.414 \, \text{m}^3.\]
Rounded to the nearest tenth, the volume is approximately $\boxed{11,635.4 \, \text{m}^3}$.
To find the volume of a right circular cone, you can use the formula:
Volume = (1/3) * π * r^2 * h
where r is the radius of the base and h is the height of the cone.
In this case, the radius (r) is given as 19.3 m and the height (h) is given as 18.8 m. Substitute these values into the formula:
Volume = (1/3) * π * (19.3)^2 * 18.8
Now, let's calculate the volume using the formula:
Volume = (1/3) * 3.14159 * (19.3)^2 * 18.8
Volume = (1/3) * 3.14159 * 373.69 * 18.8
Volume ≈ 39753.67248 cubic meters
Rounding to the nearest tenth, the volume of the right circular cone is approximately 39753.7 cubic meters.