Nitric acid appears to “dissolve” solid lead(II) hydroxide.
Products, Balanced equation, Total ionic equation and
Net ionic equation
The reaction between nitric acid and solid lead(II) hydroxide can be represented by the following balanced equation:
2 HNO3 + Pb(OH)2 -> Pb(NO3)2 + 2 H2O
In this reaction, nitric acid (HNO3) reacts with solid lead(II) hydroxide (Pb(OH)2) to form lead(II) nitrate (Pb(NO3)2) and water (H2O).
The total ionic equation for this reaction can be written as:
2 H+ + 2 NO3- + Pb2+ + 2 OH- -> Pb2+ + 2 NO3- + 2 H2O
In the total ionic equation, all soluble ionic compounds are written as separate ions.
The net ionic equation is obtained by removing the spectator ions (ions that are present on both sides of the equation) from the total ionic equation. In this case, the net ionic equation is:
2 H+ + 2 OH- -> 2 H2O
The lead(II) nitrate (Pb(NO3)2) does not participate in the net ionic equation as it remains in solution.