Calculate the height from which a body is released from rest of it's velocity just before hitting the ground is 30ms/s
To calculate the height from which a body is released, we can use the laws of motion.
First, let's assume that the acceleration due to gravity is approximately 9.8 m/s² (this value may vary depending on the location).
The final velocity of the body just before hitting the ground is given as 30 m/s, but this is the magnitude of the velocity vector. Since the body is moving downward, the velocity is negative.
We can use the equation of motion:
v² = u² + 2as,
where v is the final velocity (30 m/s), u is the initial velocity (0 m/s as the body is released from rest), a is the acceleration (-9.8 m/s²), and s is the displacement (the height h we want to find).
Plugging in the given values, the equation becomes:
(30 m/s)² = (0 m/s)² + 2(-9.8 m/s²)h.
Simplifying the equation:
900 m²/s² = -19.6 m/s² * h.
Rearranging the equation to solve for h:
h = 900 m²/s² / (-19.6 m/s²).
Calculating h:
h ≈ -45.92 meters.
The height from which the body is released (while considering the downward direction as negative) is approximately 45.92 meters.