During a softball game, a batter hits a ball upward from an initial height of 3 feet. The height, in feet, of the softball is given by s(t) = -16t^2 + 70t + 3, where t is the time in seconds. What is the time when the softball will be 50 feet above the ground?
To find the time when the softball will be 50 feet above the ground, we need to set the equation s(t) = -16t^2 + 70t + 3 equal to 50 and solve for t.
So, we have:
-16t^2 + 70t + 3 = 50
Rearranging the equation, we get:
-16t^2 + 70t + 3 - 50 = 0
Bringing like terms together, we have:
-16t^2 + 70t - 47 = 0
Now, we can solve the quadratic equation.