Ten less than twice a number is equal to at most 52. What are all the possible values of the number? Inuk wrote the inequality 2x−10≤52, where x equals the number, to help solve this problem. Solve his inequality. Use the letter x as your variable and write your x term first.%0D%0A%0D%0ANote: You will find the option to add a >%0D%0A>%0D%0A, <%0D%0A<%0D%0A, ≥%0D%0A≥%0D%0A, or ≤%0D%0A≤%0D%0A symbol in the Comparison (<)%0D%0A(%0D%0A<%0D%0A)%0D%0A keyboard.%0D%0A%0D%0A(1 point)
2x - 10 ≤ 52
please try 1 more time it is wrong :(
My apologies for the mistake. Let's try solving the inequality again.
2x - 10 ≤ 52
To isolate the variable x, we'll add 10 to both sides:
2x ≤ 62
Now, divide both sides by 2 to solve for x:
x ≤ 31
Therefore, the possible values for the number (x) are any number less than or equal to 31.
To solve the inequality 2x - 10 ≤ 52, we need to isolate the variable x.
First, add 10 to both sides of the inequality:
2x - 10 + 10 ≤ 52 + 10
2x ≤ 62
Next, divide both sides of the inequality by 2 to solve for x:
(2x)/2 ≤ 62/2
x ≤ 31
So the solution to the inequality is x ≤ 31.
Therefore, all the possible values of the number are any real numbers less than or equal to 31.