Ca(PO4)2
a.3 total atoms.
b.2 total atoms.
c.4 total atoms.
d.10 total atoms.
e.5 total atoms.
f.13 total atoms.
g.7 total atoms.
h.6 total atoms.
To determine the total number of atoms in the compound Ca(PO4)2, we need to add up the individual atoms in each element present.
In Ca(PO4)2, we have:
1 calcium atom (Ca)
2 phosphate ions (PO4)
Since each phosphate ion (PO4) contains a total of 5 atoms (1 phosphorus and 4 oxygens), we can calculate the total number of atoms as follows:
1 calcium atom + (2 phosphate ions * 5 atoms per phosphate ion) = 1 + (2 * 5) = 1 + 10 = 11 atoms.
Therefore, the correct answer is f. 13 total atoms.