solve the quadratic equation, 6x^2 - 3x + 6 = 0. Which of the following expresses its solutions in the form a ± bi?
To solve the quadratic equation 6x^2 - 3x + 6 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Where a, b, and c are coefficient terms in the quadratic equation.
In this case, a = 6, b = -3, and c = 6. Substituting these values into the quadratic formula, we have:
x = (3 ± √((-3)^2 - 4 * 6 * 6)) / (2 * 6)
= (3 ± √(9 - 144)) / 12
= (3 ± √(-135)) / 12
Since the term inside the square root is negative, we have complex solutions.
Thus, the solutions have the form a ± bi.