Step by step bot answer this please Ashortstop is standing in the base path between second base and third base when she fields the ball she is 34 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest 10th there are 3 bases and she is right next tot eh second one and the base 2 and 3 are 35 feet and 1st and second are 90 It’s a right triangle and it’s not 96.1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9
To find the distance the shortstop needs to throw the ball from second base (point A) to first base (point C), we can use the Pythagorean theorem. Let's assume point B is the third base.
1. Calculate the distance between second and third base (AB):
AB = √(35^2 + 35^2)
AB = √(1225 + 1225)
AB = √2450
AB ≈ 49.5 feet (rounded to nearest tenth)
2. Calculate the distance between first base and second base (AC):
AC = 90 feet
3. Using the Pythagorean theorem, we can find the distance the shortstop needs to throw the ball (BC):
BC = √(AC^2 - AB^2)
BC = √(90^2 - 49.5^2)
BC ≈ √(8100 - 2450)
BC ≈ √5650
BC ≈ 75.2 feet (rounded to nearest tenth)
Therefore, the shortstop needs to throw the ball approximately 75.2 feet from second base to first base.
You’re wrong I’m just wanting to know I’m a math teacher and I know this is wrong so can you give me the real answerb
Apologies for any confusion. Let's go through the calculation again.
Given:
Distance between second and third base (AB) = 35 feet
Distance between first and second base (AC) = 90 feet
Using the Pythagorean theorem, we can find the distance the shortstop needs to throw the ball (BC):
BC = √(AC^2 - AB^2)
BC = √(90^2 - 35^2)
BC = √(8100 - 1225)
BC = √6875
BC ≈ 82.9 feet (rounded to nearest tenth)
Therefore, the shortstop needs to throw the ball approximately 82.9 feet from second base to first base.
To solve this problem, we can use the Pythagorean theorem. The theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides.
In this case, we have a right triangle formed by the distance from the shortstop to the second base (34 feet), the distance from the second base to the first base (90 feet), and the distance the shortstop needs to throw the ball (which we'll call 'x' feet).
Using the Pythagorean theorem, we can set up the equation:
34^2 + x^2 = 90^2
Now, let's solve this equation step by step:
Step 1: Calculate the square of the second base to first base distance:
90^2 = 8100
Step 2: Subtract the squared second base to first base distance from both sides of the equation:
34^2 + x^2 - 8100 = 0
Step 3: Simplify and solve for x^2:
x^2 = 8100 - 34^2
x^2 = 8100 - 1156
x^2 = 6944
Step 4: Take the square root of both sides of the equation to solve for x:
x = √6944
Step 5: Round the answer to the nearest 10th:
x ≈ 83.4 feet
Therefore, the shortstop needs to throw the ball approximately 83.4 feet to first base.