A shortstop is standing in the base path between second base and third base when she fields the ball she is 34 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest 10th there are 3 bases and she is right next tot eh second one and the base 2 and 3 are 35 feet and 1st and second are 90 It’s a right triangle

Using the right triangle formed by the shortstop, second base, and first base, we can apply the Pythagorean theorem.

Let x be the distance the shortstop needs to throw the ball. Then, according to the Pythagorean theorem, we have:

x^2 = (35^2) + (90^2)

x^2 = 1225 + 8100

x^2 = 9325

x ≈ 96.5 feet

Therefore, the shortstop needs to throw the ball approximately 96.5 feet to first base.