A 50 gram glass holds 400 grams of liquid water and 75 grams of ice. After 20 minutes the mass of ice is 50 grams. In 1-2 sentences, assuming no evaporation or sublimation has occurred, calculate the mass of the liquid water at this time and explain how this is found.(2 points)

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Answer 1

Since no evaporation or sublimation has occurred, the mass of the liquid water remained constant at 400 grams throughout the 20 minutes.