A 0.6 kg object moves at a constant velocity of 2 m/s, traveling a total distance of 30 m. Using the work-energy theorem, what is the net work on the object?(1 point)
Responses
36 J
36 J
1.2 J
1.2 J
0 J
0 J
2.4 J
The net work done on an object can be calculated using the formula:
Net work = Change in kinetic energy
Since the object is moving at a constant velocity, its kinetic energy does not change. Therefore, the net work done on the object is equal to 0 J.
To find the net work on the object using the work-energy theorem, we can use the equation:
Net work = change in kinetic energy
The change in kinetic energy can be calculated using the equation:
Change in kinetic energy = 1/2 * mass * (final velocity)^2 - 1/2 * mass * (initial velocity)^2
Given:
Mass (m) = 0.6 kg
Initial velocity (v₁) = 0 m/s (since the object starts from rest)
Final velocity (v₂) = 2 m/s
Plugging in the values into the equation, we have:
Change in kinetic energy = 1/2 * 0.6 kg * (2 m/s)^2 - 1/2 * 0.6 kg * (0 m/s)^2
= 1/2 * 0.6 kg * 4 m^2/s^2 - 1/2 * 0.6 kg * 0 m^2/s^2
= 0.6 kg * 2 m^2/s^2
= 1.2 J
Therefore, the net work on the object is 1.2 J.