fill in the blank
The two-digit___ number 1 is divisible by 9.
The two-digit _______ number 1 is divisible by 9.
The two-digit ___ number 1 is divisible by 9.
To find the missing word, let's think about the divisibility rule for 9. According to the rule, a number is divisible by 9 if the sum of its digits is divisible by 9.
In the case of a two-digit number, let's assume the first digit is "x" and the second digit is "y". So, the two-digit number can be represented as "10x+y".
The number 1 cannot be the first digit because it would make the number a one-digit number, not a two-digit number.
Therefore, the missing word is the second digit, which is represented by the variable "y". To make the number divisible by 9, any digit from 0 to 9 can replace "y". So, the complete sentence would be:
The two-digit "y" number 1 is divisible by 9.
To fill in the blank, we need to find a two-digit number that is divisible by 9. The keyword "divisible by 9" tells us that the sum of the digits in the number must be a multiple of 9.
To find a suitable two-digit number, we can start by listing down all the two-digit numbers (10 to 99) and check if their digits sum up to a multiple of 9 until we find the correct number.
Let's list down the two-digit numbers:
10, 11, 12, 13, 14, 15, 16, 17, 18, 19,
20, 21, 22, 23, 24, 25, 26, 27, 28, 29,
...
90, 91, 92, 93, 94, 95, 96, 97, 98, 99.
Next, let's calculate the sum of the digits for each number and determine if it is divisible by 9. For example:
For 10, the sum of its digits is 1 + 0 = 1.
For 11, the sum of its digits is 1 + 1 = 2.
For 12, the sum of its digits is 1 + 2 = 3.
...
For 18, the sum of its digits is 1 + 8 = 9.
As we continue, we'll find that the two-digit number 99 is the first number where the sum of its digits (9 + 9 = 18) is a multiple of 9.
Therefore, the correct answer is:
The two-digit number 99 is divisible by 9.