A 2 kg ball is launched upward and has a kinetic energy of 25 J. Solve for the velocity of the ball as it was launched.(1 point)
Responses
5 m/s
5 m/s
25 J
25 J
12.5 J
12.5 J
50 m/s
50 m/s
To solve for the velocity of the ball as it was launched, we can use the formula for kinetic energy:
Kinetic energy = (1/2) * mass * velocity^2
Given kinetic energy = 25 J and mass = 2 kg, we can rearrange the formula to solve for velocity:
25 J = (1/2) * 2 kg * velocity^2
Simplifying the equation:
50 J = 2 kg * velocity^2
Dividing both sides by 2 kg:
25 = velocity^2
Taking the square root of both sides:
velocity = √25
velocity = 5 m/s
Therefore, the velocity of the ball as it was launched is 5 m/s.
To solve for the velocity of the ball as it was launched, we can use the formula for kinetic energy:
Kinetic Energy = (1/2) * mass * velocity^2
Given that the kinetic energy is 25 J and the mass of the ball is 2 kg, we can rearrange the equation to solve for velocity:
25 J = (1/2) * 2 kg * velocity^2
First, let's simplify the equation:
25 J = 1 kg * velocity^2
Now, let's solve for velocity:
velocity^2 = 25 J / 1 kg
velocity^2 = 25 m^2/s^2
Taking the square root of both sides, we get:
velocity = √(25 m^2/s^2)
velocity = 5 m/s
Therefore, the velocity of the ball as it was launched is 5 m/s.
To solve for the velocity of the ball, we can use the formula for kinetic energy:
KE = 1/2 * m * v^2
Where KE is the kinetic energy, m is the mass of the ball, and v is the velocity.
Given that the mass of the ball is 2 kg and the kinetic energy is 25 J, we can substitute these values into the equation and solve for v:
25 J = 1/2 * 2 kg * v^2
Simplifying the equation gives:
25 J = 1 kg * v^2
Dividing both sides of the equation by 1 kg gives:
25 J / 1 kg = v^2
25 m^2/s^2 = v^2
Taking the square root of both sides gives:
v = sqrt(25 m^2/s^2)
v = 5 m/s
Therefore, the velocity of the ball as it was launched is 5 m/s.